Question

starting from a stationary position, kahul puddles his bicycle to attain a velocity of 6ms^-1 in 30s. Then he applies brakes such that the velocity of the bicycle comes down to 4ms^-1 in the next 5s . Calculate the acceleration of the bicycle in both the cases.​

Answer 1

CASE 1 :-

initial velocity = 0 m/s

final velocity = 6 m/s

time = 30 s

$acceleration = \frac{v - u}{t}$

acceleration = 6-0/30

acceleration = 6/30

acceleration = 1/5 or 0.2 m/s²

therefore, the acceleration of Kahul's bicycle in case 1 is 0.2 m/s² or 1/5 m/s²

CASE 2 :-

initial velocity = 6 m/s

final velocity = 4 m/s

time = 5 s

$acceleration = \frac{v - u}{t}$

acceleration = 4-6/5

acceleration = -2/5

acceleration = -0.4 m/s²

therefore, the acceleration of Kahul's bicycle in case 2 is -0.4 m/s² or the retardation of 0.4 m/s²

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