Starting from a stationary position Rahul paddles bicycles. To attain a velocity of 6ms in 30 sec then applies breaks such that velocity of bicycle comes down to 4ms in the next 5 sec calculate the acceleration of bicycle in both the cases
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Case 1 :
Given:
u= 0m/s
v= 6m/s
t= 30s
a= u+v/t (first equation of motion)
a= 0+6/30
a= 6/30 = 1/5
=> a= 0.2m/s
Case 2 :
Given:
u=6m/s
v=4m/s
t=5s
a= u+v/t ( first equation of motion)
a= 6+4/5
a= 10/5
=> a=2m/s
So In the first case, acceleration is 0.2 m/s. In the second case, acceleration is 2m/s.
HOPE THIS HELPS !!
Given:
u= 0m/s
v= 6m/s
t= 30s
a= u+v/t (first equation of motion)
a= 0+6/30
a= 6/30 = 1/5
=> a= 0.2m/s
Case 2 :
Given:
u=6m/s
v=4m/s
t=5s
a= u+v/t ( first equation of motion)
a= 6+4/5
a= 10/5
=> a=2m/s
So In the first case, acceleration is 0.2 m/s. In the second case, acceleration is 2m/s.
HOPE THIS HELPS !!
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