Question

Starting from a stationary position , rahul paddles his bicycle to attain a velocity of 6m/s in 30 s. then he applies brakes such that the velocity of the bicycle comes down to 4m/s in the next 5s. calculate the acceleration of the bicycle in both the cases.

Answer 1

first case acc is 0.2ms^-1 and in second case deacceleration is 0.4ms^-1

Answer 2

Answer:

$\huge\bf\red{AnsWer:}$

In the first case :

• Initial velocity , u = 0
• Final velocity , v = 6m/s
• time , t = 30 s

Therefore , a = acceleration =

$\bf\green{a = v-u/t}$

➡️ 6-0/30

➡️ 0.2ms²

In the second case :

• initial velocity ,u = 6m/s
• final velocity , v = 4m/s
• time,t = 5s

Therefore acceleration =

a = v-u/t

➡️ 4-6/5

➡️ -0.4ms²

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