Starting from a stationary position, Rahul paddles his
bicycle to attain a velocity of 6 m s–1 in 30 s. Then he applies brakes
such that the velocity of the bicycle comes down to 4 m s-1 in the
next 5 s. Calculate the acceleration of the bicycle in both the cases.
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Answers
Answered by
2
Answer:
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Explanation:
Solution
For first case:
Initial velocity =0
Final velocity =60m/s
Time =30sec
v=u+at
6=0+a×30
6=30a
a=
30
6
=0.2
a=0.2m/s
2
For second case:
Initial velocity =6m/s
Final velocity =4m/s
Time taken =5sec
v=u+at
4=6+a×5
4−6=5a
−2=5a
a=−
5
2
a=−0.4m/s
2
Answered by
1
Answer:
For first case:
Initial velocity =0
Final velocity =60m/s
Time =30sec
v=u+at
6=0+a×30
6=30a
a=
30
6
=0.2
a=0.2m/s
2
For second case:
Initial velocity =6m/s
Final velocity =4m/s
Time taken =5sec
v=u+at
4=6+a×5
4−6=5a
−2=5a
a=−
5
2
a=−0.4m/s
2
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