Question

Starting from a stationary position rehan paddles his bicycle to attain a velocity of 6m/s in 30s then he applies break such that the velocity of bicycle comes down to 4m/s in next 5s calculate the acceleration of bicycle in both the cases

Answer 1

here u = initial velocity, v = final velocity, t = time, a = acceleration
1st case
u = 0m/s
v = 6m/s
t= 30s
a =v-u/t = 6-0/30 = 6/30 = 0.2 m/s∧2

2nd case
u = 6m/s
v = 4m/s
t = 5s
a = 4-6/5 = -2/5 = -0.4 m/s∧2

Answer 2

Answer:

$\huge\bf\red{AnsWer:}$

In the first case :

• Initial velocity , u = 0
• Final velocity , v = 6m/s
• time , t = 30 s

Therefore , a = acceleration =

$\bf\pink{a = v-u/t}$

➡️ 6-0/30

➡️ 0.2ms²

In the second case :

• initial velocity ,u = 6m/s
• final velocity , v = 4m/s
• time,t = 5s

Therefore acceleration =

$\bf\pink{a = v-u/t}$

➡️ 4-6/5

➡️ -0.4ms²