Question

Starting from a stationary position, Rohan starts his bicycle to attain a velocity of
9km/h in
20 s. calculate acceleration of the cycle​

Answer 1

For first case:

Initial velocity =0

Final velocity =60m/s

Time =30sec

v=u+at

6=0+a×30

6=30a

a=

30

6

=0.2

a=0.2m/s

2

For second case:

Initial velocity =6m/s

Final velocity =4m/s

Time taken =5sec

v=u+at

4=6+a×5

4−6=5a

−2=5a

a=−

5

2

a=−0.4m/s

2

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Answer 2

Step-by-step explanation:

Given that, starting from a stationary position, Rohan starts his bicycle to attain a velocity of 9km/h in 20 s.

We have to find the acceleration of the cycle.

Firstly convert km/hr into m/s. To do this multiply the given value by 5/18.

→ v = 9 × 5/18 = 2.5 m/s

From above data we have, u is 0m/s (as it starts from stationary position), v is 2.5 m/s, t is 20 s.

Using the first equation of motion,

v = u + at

Substitute the values,

→ 2.5 = 0 + a(20)

→ 2.5/20 = a

→ 0.125 = a

Hence, the acceleration of the cycle is 0.125 m/s².