Question

Starting from her house, Nita walks 160m north and then 630m west to reach a friend's house.on her way back ,she walks diagonally until she reaches her own house.what distance did she walk while coming back?

Answer 1

While returning she covers 650 m.
By using Pythagoras Theorem
AB^2+BC^2=AC^2
Here,
AB=160m
BC=630m
Therefore AC=Square root of AB^2+BC^2=650m
Hope this will be helpful. Thanks.

Answer 2

Answer:Here is pythagoeran theoram used so

Psquare +b square = hsquare

160 square +630square=xsquare

25600+386900

=412500 then to remove the square from x we will find the square of 412500 =650

Step-by-step explanation: