Starting from her house, Nita walks 160m north and then 630m west to reach a friend's house.on her way back ,she walks diagonally until she reaches her own house.what distance did she walk while coming back?
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Answered by
3
While returning she covers 650 m.
By using Pythagoras Theorem
AB^2+BC^2=AC^2
Here,
AB=160m
BC=630m
Therefore AC=Square root of AB^2+BC^2=650m
Hope this will be helpful. Thanks.
Answered by
1
Answer:Here is pythagoeran theoram used so
Psquare +b square = hsquare
160 square +630square=xsquare
25600+386900
=412500 then to remove the square from x we will find the square of 412500 =650
Step-by-step explanation:
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