Math, asked by Lakshay2690, 1 year ago

Starting from his home, mohan reaches his office 5 minutes late when he drives his bike at 24 km/hr. If he drives 25% faster on an average, he reaches his office 4 minutes earlier than the scheduled time. What is the distance of his office from his home?

Answers

Answered by GauravSaxena01
2

Answer:

Let x km be the gap between his house and office.

while the travelling at 24 kmph,  

he would take = x /24 hours  

while motion at 25 faster speed  

24+25% of 24 = 24 × 1/4

=> 30 kmph

He would take x/30 hours  

now as per the problem,  

time distinction = 5 min late +4 min early = 9 min  

=> x/24-x/30 = 9 min  

=> x=18 km

the distance of his office from his home is 18 km

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@GauravSaxena01

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