Starting from his home, mohan reaches his office 5 minutes late when he drives his bike at 24 km/hr. If he drives 25% faster on an average, he reaches his office 4 minutes earlier than the scheduled time. What is the distance of his office from his home?
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Answer:
Let x km be the gap between his house and office.
while the travelling at 24 kmph,
he would take = x /24 hours
while motion at 25 faster speed
24+25% of 24 = 24 × 1/4
=> 30 kmph
He would take x/30 hours
now as per the problem,
time distinction = 5 min late +4 min early = 9 min
=> x/24-x/30 = 9 min
=> x=18 km
the distance of his office from his home is 18 km
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@GauravSaxena01
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