Question

starting from Madhav's house,John first goes 12m to North ,then 73m to west ,then 67m to South and finally 25m to east and reaches Mohammad's house.Then what is the direct distance between Madhav's and Mohammad's houses.
( give answer with detail information)​

Answer 1

Step-by-step explanation:

Given Starting from Madhav's house, John first goes 12 m to North ,then 73 m to west ,then 67 m to South and finally 25 m to east and reaches Mohammad's house. Then what is the direct distance between Madhav's and Mohammad's houses.

• So John first goes 12 m to North, 73 m to west, 67 m to south and finally 25 m to east. So we need to find the direct distance from Madhav’s house to Mohammad’s house.
• So assume this distance as m. After drawing a perpendicular to the direction of square we get a triangle at the end joining both the houses. So a right angled triangle is formed at the corner.
• So by using Pythagoras theorem we get
•                      AC^2 = AB^2 + BC^2  
•                        AB = 73 – 25 = 48 m
•                         BC = 67 – 12 = 55 m
•                      AC^2 = 55^2 + 48^2
•                               = 3025 + 2304
•                                = 5329
•                        AC = √5329
•                        AC = 73 m
• So the direct distance from Madhav’s house to Mohammad’s house to 73 m

Reference link will be

https://brainly.in/question/7467982