Chemistry, asked by aadi316, 4 months ago

Starting from PCI(9), for the reaction PCIS (9) FPC13(9) + Cl2(9) at 90°C vapour density of the
equilibrium mixture is 60. Determine the degree of dissociation of PCI (9) at 90°C:
(1) 1
(2) 0.74 (3) 0.34
(4) None of these​

Answers

Answered by abimanyupradhan
0

Answer:

yuien reaction ate

P(l5(g)⇌P(l3(g)+C2Cg)

we kuore that

α=Mi−MfMf(n−1)

where M∘i= Mol. mass before dissocialion Mf= Mol. mass after dissociation h= woop woles of product

MiMfh∴0=31+5×35.5=208.5=2×V0D0=2×100=200=2α=208.5−200200(2−1)=4.25100

Hewce "/ o dissociation of PLes= α×100

4.25100×100

also kuous that =4.25% 4 wotes at equifibritum =1+2(n−1)

=1+4.25100(2−1)=1.0425

Total bressure at equiclibrilum PV=nRT

P=1.0425×0.082×30010=2.57 atm

Explanation:

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