Question

Starting from point A, Sid walks 12 m towards North and then he turns right and walks 12 m. Then,
he turns right and walks 3 m. How far, and in which direction, is Sid now with respect to the starting
point?​

Answer 1

$\LARGE{ \underline{\underline{ \sf{Required \: answer:}}}}$

Refer to attachment -1)

Steps Taken by Sid according to directions in 2)

• 12 m towards North.
• He turn right and walks 12 m.
• He again turns right and walks 3 m.

It means AC = 12 m, CD = 12 m and DE = 3 m. Then, BE = 12 m, AB = 12 m - 3 m = 9 m.

In right angled ∆ABE,

➛ AB² + BE² = AE²

➛ 9² + 12² = AE²

➛ AE = √225 m

➛ AE = 15 m.

Here, A is the Initial/Starting point and E is the final point. With respect to directions, E is in the North-east (NE) direction of A.

Hence,

The distance between the starting and final point and the direction is:

$\huge{ \boxed{ \red{ \sf{15m, \: North - east}}}}$

Answer 2

Question

Starting from point A, Sid walks 12 m towards North and then he turns right and walks 12 m. Then, he turns right and walks 3 m. How far, and in which direction, is Sid now with respect to the starting point?

Solution

Sid works 12m towards North.

He turns right and walks 12m from North.

Then he turns right and walks 3m.

AB = 12m

BC = 12m

CD = 3m

DE = 12m

BE = 3m

AE =m

AD = ?

Now we have to find out the distance of Sid with respect to the starting point i.e AD (By Pythagoras theorem)

ATP

AD² = AE²+DE²

=) AD² = (12)²+(9)²

=) AD² = 144+81

=) AD² = 225

=) AD = √225 = 15

Ans:- Distance is 15m. Direction is North East.

Refer to the above diagram.