Question

Starting from rest, a 1.00 kg crate is accelerated across a floor at a rate of 3.0 m/s^2 for 0.50 minutes. How much net work (J) is done on the box

Answer 1

Answer:

4050J

Explanation:

Work = force x displacement

W = ma x s

to determine the displacement, use

$s=ut+\frac{1}{2} at^2$

its given that the crate starts from rest ie, u = 0

s = 1/2 x 3 x 30 x 30 meters         (convert 0.5 mins to seconds)

      1350m

work = 1 x 3 x 1350

          4050 joules

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