Question

Starting from rest a bike gains steady acceleration 3 m/s2 for 15s. find the speed

Answer 1

Given:-

• Initial velocity ,u = 0m/s

• Acceleration ,a = 3m/s²

• Time taken ,t = 15

To Find:-

• Final Velocity ,v

Solution:-

We have to calculate the final velocity of the bike .So by using 1st Equation of Motion.

• v = u +at

where,

v is the final velocity

a is the acceleration

u is the initial velocity

t is the time taken

Substitute the value we get

→ v = 0 + 3×15

→ v = 0+ 45

→ v = 45m/s

Therefore, the final velocity of the bike is 45 m/s.

Additional Information !!

Some equation of motion are

• v = u +at

• s = ut +1/2at².

• v² = u² + 2as

Here,

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement or Distance

t is the time taken

Answer 2

$\huge{\boxed{\rm{\red{Correct \: question}}}}$

Starting from rest a bike gains steady acceleration 3 m/s² for 15s. Find the speed.

$\huge{\boxed{\rm{\red{Answer}}}}$

$\large{\boxed{\boxed{\sf{Given \: that}}}}$

• Initial velocity = 0 m/s.

• Time taken = 15 seconds.

• Acceleration = 3 m/s².

$\large{\boxed{\boxed{\sf{To \: find}}}}$

• Speed of the bike / Final velocity.

$\large{\boxed{\boxed{\sf{Solution}}}}$

• Speed of the bike / final velocity = 45 m/s

$\large{\boxed{\boxed{\sf{We \: also \: write \: these \: as}}}}$

• Final velocity as V.

• Initial velocity as U.

• Acceleration as A.

• Time as T.

$\large{\boxed{\boxed{\sf{What \: the \: question \: says}}}}$

$\large{\boxed{\boxed{\sf{Let's \: understand \: the \: concept \: 1st}}}}$

• In this question there is a bike. It's start it's acceleration at 3 m/s². It takes the time of 15 seconds. It's initial velocity will be 0 m/s. Now the question asked that find the final velocity / speed of the bike.

$\large{\boxed{\boxed{\sf{How \: to \: do \: this \: question}}}}$

$\large{\boxed{\boxed{\sf{Procedure \: of \: the \: question \: is \: given \: below}}}}$

• In this question firstly we have to know the formula of Newton's first law of motion . And we know that the formula is v = u + at. After that substituting the values according to this rule / formula we get result 45 m/s . And it's our final result . Hence, 45 m/s is the spped /final velocity of the bike. We have done :)

$\large{\boxed{\boxed{\sf{Full \: solution}}}}$

As we know that we have to find final velocity / speed of the bike so, we have to use the formula of Newton's first law of motion –

We know that Formula of Newton's first law of motion is v = u + at

$\small\purple{\texttt{Substituting the values we get}}$

↝ 0 + 3 × 15

↝ 0 + 45

↝ 45 m/s

Therefore, the final velocity / speed of the bike will be 45 m/s.

$\bold{\green{\fbox{\green{45 m/s \: is \: final \: velocity.}}}}$

$\huge{\boxed{\rm{\red{Explore \: more \: information \: !}}}}$

$\large{\boxed{\boxed{\sf{Newton's \: 1st \: law \: of \: motion}}}}$

$\small\pink{\texttt{Formula :}}$ v = u + at

$\large{\boxed{\boxed{\sf{Newton's \: 2nd \: law \: of \: motion}}}}$

$\small\pink{\texttt{Formula :}}$ s = ut + 1/2at²

$\large{\boxed{\boxed{\sf{Newton's \: 3rd \: law \: of \: motion}}}}$

$\small\pink{\texttt{Formula :}}$ v² = u² + 2as

Hope it's helpful

Thank you :)