Question

starting from rest a body attains a speed of 4 m/s. Find it's acceleration​

Answer 1

Question :

Starting from rest a body attains a speed of 4 m/s.Find it's acceleration

Given :

• Initial velocity ,u= 0 m/s
• Final velocity , v = 4 m/s

To Find :

Acceleration of the body

${\purple{\boxed{\large{\bold{Formula's}}}}}$

Kinematic equations for uniformly accelerated motion.

$\bf\:v=u+at$

$\bf\:S=ut+\frac{1}{2}at{}^{2}$

$\bf\:v{}^{2}=u{}^{2}+2aS$

and $\bf\:s_{nth}=u+\frac{a}{2}(2n-1)$

Solution :

We have to the Acceleration of the body.

Let the time interval be " t "

By First Equation of motion

$\rm\:v=u+at$

Put the given values

$\sf\implies\:4=0+a\:\times\:t$

$\sf\implies\:at=4$

$\sf\implies\:a=\dfrac{4}{t}ms^{-2}$

Therefore, Acceleration of the body is (4/t) m/s²

Answer 2

Answer:

Given :-

• Starting from rest a body attains a speed of 4 m/s.

Find Out :-

• Acceleration.

Formula Required :-

We know that,

✰ v = u + at ✰

【 where, v = Final Velocity, u = Initial Velocity, a = Acceleration, t = Time 】

Solution :-

Given :

• u = 0 m/s
• v = 4 m/s

According to the question,

➛ 4 = 0 + at

➛ 4 = at

➛ $\tt{\dfrac{4}{t}}$ = a

➡ $\tt{a =\: \dfrac{4}{t}\:m/s²}$

$\therefore$ The acceleration of a body is $\tt{\dfrac{4}{t}\: m/s²}$.