Starting from rest a body attends a velocity of 36 km/h in 5sec . Calculate its acceleration
Answers
Answered by
1
First of change 36km/h in m/s.
(36x5/18)m/s=10m/s
we know that,
a=v-u/t
a=10-0ms-¹/5sec
a=2m/s².
Hope it helps...
(36x5/18)m/s=10m/s
we know that,
a=v-u/t
a=10-0ms-¹/5sec
a=2m/s².
Hope it helps...
Answered by
1
Hi..
u=0 m/ s
v=36 km / hr = 10 m / s
t=5 sec
a= ?
By using
v = u + a * t
Thus ;
a = v - u / t
a = 10 -0 / 5
a = 2 m/ s ^2...
Hope this helps u!
u=0 m/ s
v=36 km / hr = 10 m / s
t=5 sec
a= ?
By using
v = u + a * t
Thus ;
a = v - u / t
a = 10 -0 / 5
a = 2 m/ s ^2...
Hope this helps u!
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