Question

Starting from rest a body travels 36m in the first 2 second of journey. Distance it can travel in the 11th second is ?

Answer 1

Answer: The body travels 1089 m in the 11 sec

Explanation:

Given that,

Initial velocity u = 0

Time t = 2 sec

Distance s = 36 m

Using equation of motion

$s =ut+\dfrac{1}{2}at^{2}$

$36m = 0+\dfrac{1}{2}\times a\times 4$

$a = 18 m/s^{2}$

Now, the body travels in 11 sec

Using equation of motion

$s = ut+\dfrac{1}{2}\times a\times t^{2}$

$s = 0+\dfrac{1}{2}\times18\times (11)^{2}$

$s = 1089 m$

Hence, the body travels 1089 m in the 11 sec.

Answer 2

"Given:

Distance: 36 m

Time: 2s

Distance at 11s =?

Solution:

Initial velocity of body is given by;

u = 0

For the first 2 seconds, distance is:

s = 36 m

Using equation of motion for straight line;

$s=ut+1/2at^2$

36 = 0 + 2a

So,  a = 18 m/s2

Now, for the 11 seconds, the distance will be;        

$s=ut+1/2at^2$

s = 0 + (0.5x 18 x 121)

= 1089 m

So, the distance travelled is 1089 m"