Physics, asked by balaji3312, 1 year ago

Starting from rest a body travels 36m in the first 2 second of its journey. Distance it can travel in the 11th second is ?

Answers

Answered by abhishekbrainly61
1
by second eq. of motion acce.=18
again by second eq. s=1089
Answered by ArnavC1605
1

Answer:

189m

Explanation:

body starts from rest so u = 0.

in first 2 seconds body travels 36m

so t = 2s

s = 36m

to find acceleration

s = ut+1/2*at^2

36 = 0 + 1/2 * a + 4

a = 18m/sec^2

now to find distance after 11 seconds:

sn = u + a/2(2n-1)

=18/2(2*11 - 1)

=9*21

=189m

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