Question

Starting from rest a car acquired a velocity of 16m/s in 4s.If mass of the cart is 3kg Find Force acting on it.Also find Distance travelled by the car .

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Answer 1

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Distance covered by car is 32 metres.

Force acting on it is 12 newton.

Explanation:

According to the Question

It is given that

Initial velocity ,u = 0m/s

Final velocity ,v = 16m/s

Time taken ,t = 4s

Mass of cart ,m = 3kg

we need to calculate the force acting on it and distance covered by it .

Firstly we calculate the acceleration of the car .

Using Kinematics Equation

v = u + at

Putting all the value we get

➺ 16 = 0 + a×4

➺ 16 = 4×a

➺ a = 16/4

➺ a = 4m/s²

So, the acceleration of the car is 4m/s².

As we know that Force is calculated by the product of mass and acceleration .

F = ma

substitute the value we get

➺ F = 3×4

➺ F = 12N

Hence, the force acting is 12 newton.

Now, calculating the distance covered by car in given condition.

again using Kinematics Equation

v² = u² + 2as

substitute the value we get

➺ 16² = 0² + 2×4 ×s

➺ 256 = 0 + 8 × s

➺ 256 = 8×s

➺ s = 256/8

➺ s = 32m

Hence, the distance covered by the car is 32 metres.

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:Mass of the body, m = 3 kg

Initial speed of the body, u = 2 m/s

Final speed of the body, v = 3.5 m/s

Time, t = 25 s

Using the first equation of motion, the acceleration (a) produced in the body can be calculated as:

v=u+at

a=  

t

(v−u)

​  

 

  =  

25

(3.5−2)

​  

=0.06m/s  

2

 

As per Newton's second law of motion, force is given as:

F=ma

   =3×0.06=0.18N

Since the application of force does not change the direction of the body, the net force acting on the body is in the direction of its motion.