Starting from rest a car acquired a velocity of 16m/s in 4s.If mass of the cart is 3kg Find Force acting on it.Also find Distance travelled by the car .
Answers
Answer:
Answer:
Distance covered by car is 32 metres.
Force acting on it is 12 newton.
Explanation:
According to the Question
It is given that
Initial velocity ,u = 0m/s
Final velocity ,v = 16m/s
Time taken ,t = 4s
Mass of cart ,m = 3kg
we need to calculate the force acting on it and distance covered by it .
Firstly we calculate the acceleration of the car .
Using Kinematics Equation
v = u + at
Putting all the value we get
➺ 16 = 0 + a×4
➺ 16 = 4×a
➺ a = 16/4
➺ a = 4m/s²
So, the acceleration of the car is 4m/s².
As we know that Force is calculated by the product of mass and acceleration .
F = ma
substitute the value we get
➺ F = 3×4
➺ F = 12N
Hence, the force acting is 12 newton.
Now, calculating the distance covered by car in given condition.
again using Kinematics Equation
v² = u² + 2as
substitute the value we get
➺ 16² = 0² + 2×4 ×s
➺ 256 = 0 + 8 × s
➺ 256 = 8×s
➺ s = 256/8
➺ s = 32m
Hence, the distance covered by the car is 32 metres.
Explanation:
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Distance covered by a car is 32 metre
Force acting on it is 12 metre
According to the question
It is given that
Intial velocity, u = 0m/s
Finial velocity ,v = 16m/s
Time taken,t = 4s
Mass of cart,m = 3kg
We need to calculate the force acting on it .
Firstly we calculate thr acceleration of the car..
Using kinematics Equation
v=u + at
Putting all the value we get
a= 4m/s²
So the acceleration of the car 4m/s²
As we know the force is calculated by thr product of mass and acceleration..
F=ma
Substite thr value we get
◇ F = 3×4
◇ F = 12n
Hence the force acting is 12 Newton
Now calculating the distance covered by car in given condition
Using kinematic equation
v²=u²+2as
Substitute the value we get
◇16²=0²+2×4×s
◇256=2+8
◇256=3×s
◇s=356/8
◇s=32m
Hence the distance covered by the car is 32 metre..