Question

Starting from rest a car acquired a velocity of 16m/s in 4s.If mass of the cart is 3kg Find Force acting on it.Also find Distance travelled by the car .​

Answer 1

Step-by-step explanation:

Given that,

,Intial velocity u=0m/sFinal velocity v=54km/h=54× 185 =15m/s Time t=2min=120sNow, put the value in equation of motionThe acceleration is v=u+at a= t/v−u

a= 120/15−0

15−0 a=o.125m/s 2

15−0 a=o.125m/s 2 Now, again from equation of motionThe distance is s=ut+ 2/1 at 2

1 at 2 s=0+ 2/1 ×0.125×120×120

×0.125×120×120 s=900m

×0.125×120×120 s=900mHence, the acceleration is 0.125m/s 2and distance is 900m

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Answer 2

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Distance covered by car is 32 metres.

Force acting on it is 12 newton.

Explanation:

According to the Question

It is given that

Initial velocity ,u = 0m/s

Final velocity ,v = 16m/s

Time taken ,t = 4s

Mass of cart ,m = 3kg

we need to calculate the force acting on it and distance covered by it .

Firstly we calculate the acceleration of the car .

Using Kinematics Equation

v = u + at

Putting all the value we get

➺ 16 = 0 + a×4

➺ 16 = 4×a

➺ a = 16/4

➺ a = 4m/s²

So, the acceleration of the car is 4m/s².

As we know that Force is calculated by the product of mass and acceleration .

F = ma

substitute the value we get

➺ F = 3×4

➺ F = 12N

Hence, the force acting is 12 newton.

Now, calculating the distance covered by car in given condition.

again using Kinematics Equation

v² = u² + 2as

substitute the value we get

➺ 16² = 0² + 2×4 ×s

➺ 256 = 0 + 8 × s

➺ 256 = 8×s

➺ s = 256/8

➺ s = 32m

Hence, the distance covered by the car is 32 metres.