Question

Starting from rest, a marble rolls along the ground to attain a velocity of 3m/s in 5 s. Calculate the rate of change of velocity of the marble.

Answer 1

Answer:

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Answer 2

$\color{red}\large\underline{\underline{Question:}}$

Starting from rest, a marble rolls along the ground to attain a velocity of 3m/s in 5 s. Calculate the rate of change of velocity of the marble.

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$\color{orange}\large\underline{\underline{To\:Find:}}$

$\underline{The\:accelaration\:of\:the\:marble}</p><p>$

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$\color{purple}\large\underline{\underline{Given::}}$

• $Initial\:velocity = 0 ms^{-1}$
• $Final\:velocity = 3 ms^{-1}$
• $Time = 5s$

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$\color{blue}\large\underline{\underline{We\:know::}}$

$\therefore Accelaration = \dfrac{v - u}{t}$

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$\color{green}\large\underline{\underline{Solution:}}$

$\Rightarrow Accelaration = \dfrac{3 - 0}{5}$

$\Rightarrow Accelaration = \dfrac{3}{5}$

${\boxed{Accelaration = \dfrac{3}{5}ms^{-2}}}$