Starting from rest acceleration of a partical is a=2(t-1) velocity of partical at t =5sec is
Answers
Answered by
38
Answer:
8 m/s²
Explanation:
Given :
- Initial velocity = u = 0 m/s
- Time = t = 5 seconds
- Acceleration = 2(t-1)
To find :
- Acceleration of the particle in the 5th second
In this question, we have to just substitute the value of t = 5 in (2t-1) and then we will get the required answer
Acceleration in 5th second = 2(5-1)
Acceleration = 2(4)
Acceleration = 8 m/s²
The acceleration of the particle is 8 m/s² in the 5th second
Answered by
200
Given:-
- Initial velocity = 0m/s
- Acceleration = 2(t-1)
- Time = 5 s
To Find:-
- Velocity of particle.
Solution :-
According to the question
By using this formula
➦ v = t² - 2t
➭ v = 5² - 2× 5
➭ v = 25 -10
➭ v = 15m/s.
∴The velocity of particle is 15m/s.
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