Question

. Starting from rest, an object accelerates at a rate of 12 m/s2. What is the velocity of the object at the end of 3 seconds?​

Answer 1

☆ Answer : ☆

• The velocity of the object after 3 seconds is 36 m/s.

☆ Given ☆

• Initial Velocity = 0 m/s (at rest)
• Acceleration = 12 m/s²
• Time = 3 seconds

☆ To Find : ☆

• Final Velocity = ?

☆ Solution : ☆

• To calculate the Final Velocity of the object here we have to apply the first equation of motion :]

By using first equation of motion we get :

• v = u + at

Where, v is Final Velocity, u is Initial Velocity, a is Acceleration and t is time.

Now, Substituting the given values in above equation we get :

→ v = 0 + 12 × 3

→ v = 12 × 3

→ v = 36 m/s

Therefore,the velocity of the object after 3 seconds is 36 m/s.

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We have the three equations of motion to make things simpler :

• v = u + at
• s = ut + ½ at²
• v² - u² = 2as

Answer 2

Given:-

▣Object is starting from rest = Initial Velocity = 0m/s

▣Acceleration = 12m/s²

▣Time = 3sec

Find:-

▫Final Velocity

Solution:-

we, know that

$\sf\underline{\boxed{\sf v = u + at}} \quad \bigg\lgroup F1^{st} eq. of motion\bigg\rgroup$

where,

• Initial Velocity, u = 0m/s
• Acceleration, a = 12m/s²
• Time, t = 3sec

So,

$\sf\dashrightarrow v = u + at$

$\sf\dashrightarrow v = 0+ (12)(3)$

$\sf\dashrightarrow v = 0+36$

$\sf\dashrightarrow v = 36m/s$

$\small{\sf\therefore v = 36m/s}$

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Hence, after 3sec velocity of object will be 36m/s