Question

Starting from rest and moving with constant
acceleration, a body covers a certain distance in
time t. It covers the last one third of the distance in
time

(1) t/√2

(2)t/√3

(3) t(1 - 1/√3)

(4) t(1 - √2/√3)


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Answer 1

Answer:

Let the time taken to cover the first half portion of the journey be t1t1 and for the second half portion be t2t2 . Then

t=t1+t2t=t1+t2

For the first half-journey, putting

S=L/2,u=0S=L/2,u=0 etc. in S=ut+12S=ut+12at2at2, we get L2L2=0+12=0+12at21at12

L2L2=0+12=0+12at21at12

As the time to complete the whole journey is t, therefore ,

L=0+12L=0+12at2at2

Dividing both equations :

L=0+12L=0+12=>t1=t2–√=>t1=t2

t2=(t−t1)=t−t2√=t[2–√−12–√]