Question

Starting from rest Joseph paddles his bicycle to attain a velocity of 10 m/s in 30s. The acceleration of the bicycle is

Answer 1

Given:

Initial velocity of bicycle, u= 0 m/s

Final velocity of bicycle, v= 10 m/s

Time taken, t= 30 s

To Find:

Acceleration of bicycle

Solution:

We know that,

• According to first equation of motion for constant acceleration,

$\purple{\boxed{\bf{v=u+at}}}$

where,

v is final velocity

u is initial velocity

a is acceleration

t is time taken

$\rule{190}{1}$

Let the acceleration of bicycle be a

On applying first equation of motion on bicycle, we get

$\longrightarrow\rm{v=u+at}$

$\longrightarrow\rm{10=0+a(30)}$

$\longrightarrow\rm{10=30a}$

$\longrightarrow\rm{30a=10}$

$\longrightarrow\rm{a=\dfrac{10}{30}}$

$\longrightarrow\rm{a=\dfrac{10}{30}}$

$\longrightarrow\rm\green{a=0.33\:m/s^{2}}$

Hence, the acceleration of the bicycle is 0.33 m/s².

Answer 2

Answer:

Explanation:

Solution,

Here, we have

Initial velocity of Joseph's bicycle, u = 0 (As starts from rest)

Final velocity of Joseph's bicycle, v = 10 m/s

Time taken by Joseph's bicycle, t = 30 seconds

To Find,

Acceleration of the bicycle, A = ?

According to the 1st equation of motion,

we know that,

v = u + at

So, putting all the values, we get

⇒ v = u + at

⇒ 10 = 0 + a × 30

⇒ 10 = 30a

⇒ 10/30 = a

⇒ a = 0.33 m/s²

Hence, The acceleration of the bicycle is 0.33 m/s².