Starting from rest on a level road a girl can reach a speed of 5m/s in 10 s on her bicycle, find
A) the acceleration
B) The average speed during the 10 s
C) the distance she travels in 10 s.
D) Eventually, even though she is still pedaling as fast as she can, she stops accelerating and her speed reaches a maximum value. Explain in terms of the forces acting why this happens.
Answers
Answered by
32
Answer:
A ) a = v - u / t
= 5 m/s - 0 / 10s
= 0.5 m/s^2
B ) av. speed = u + v / t
= 0 + 5 m/s^2 / 10s
= 0.5 m/s
C) s = ut + 1/2 at^2
= 0 * 10s + 1/2 * 0.5m/s^2 * ( 10s )^2
= 1/2 * 0.5m/s^2 * 100s
= 1/2 * 5/10m/s^2 * 100s
= 1/2 * 50 m
= 25 m
D ) ..........................
hope May it be helpful
Answered by
3
Answer:
A ) a = v - u / t
= 5 m/s - 0 / 10s
= 0.5 m/s^2
B ) av. speed = u + v / t
= 0 + 5 m/s^2 / 10s
= 0.5 m/s
C) s = ut + 1/2 at^2
= 0 * 10s + 1/2 * 0.5m/s^2 * ( 10s )^2
= 1/2 * 0.5m/s^2 * 100s
= 1/2 * 5/10m/s^2 * 100s
= 1/2 * 50 m
= 25 m
Explanation:
Similar questions