Question

Starting from rest ,the acceleration of a particle is a a 2(t -1). The velocity of the particle at t 5s
please solve​

Answer 1

Answer:

a=2(t−1)

=2t−2

Dv/dt  =2t−2

dv= (2t−2) dt

integrating both side we get,

∫ dv=∫(2t−2)dt

v=t2−2t+c

=2t−2

Dv/dt =2t−2

=(5)2−2×5

=25−10

=15m/s

Explanation:

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