Question

Starting from Sodium Chloride how would you prepare
1) Sodium metal
2) Na2O2​

Answer 1

Answer:

1.Reaction of sodium chloride with calcium carbonate

That gives us Sodium carbonate and calcium chloride

2.Conversion of sodium carbonate to its oxide through the process of calcination

3.Reduction of sodium oxide

4.Thus we obtain pure sodium metal.

Answer 2

$\huge{\orange{\underline {\overline{\boxed{\blue{\mathbb{ANSWER}}}}}}}$

$\sf {\green {\underline {\underline{ PREPARATION\: OF\: SODIUM\: METAL :}}}}$

Sodium metal is manufactured by electrolysis of fused mixture of NaCl and $\sf CaCl_2$ in down's cell at 873 K using iron cathode and graphite anode. Sodium is liberated at cathode while chloride is evolved in anode.

Reactions :

$\blue{ \boxed {\sf{ \: \: 2NaCl \: \: \longrightarrow \: \: \: 2Na^+ \: + \: 2 Cl^- }}}$

$\sf{ \underline{At \: Cathode } : \pink{\: 2 Na^+ \: + 2e \: \longrightarrow \: 2 Na}}$

$\sf{ \underline{At \: Anode} : \pink{\: 2 Cl^- \: - \: 2e \: \longrightarrow \: Cl_2}}$

_________________________________________

_________________________________________

$\sf {\green {\underline {\underline{ PREPARATION\: OF\: SODIUM\: PEROXIDE \:(Na_2 O_2):}}}}$

Sodium Peroxide is obtained by heating sodium in excess of air. The initially formed $\sf Na_2O$ reacts with more $\sf O_2$ to form $\sf Na_2 O_2.$

Reactions :

$\blue{ \boxed {\sf{ \: \: 2NaCl \: \: \longrightarrow \: \: \: 2Na^+ \: + \: 2 Cl^- }}}$

$\sf{ \underline{At \: Cathode } : \pink{\: 2 Na^+ \: + 2e \: \longrightarrow \: 2 Na}}$

$\sf{ \underline{At \: Anode } : \pink{\: Na_2 O \: + \: \frac{1}{2} O \: \longrightarrow \: Na_2 O_2 }}</p><p>$

#answerwithquality #BAL