Question

Starting from stationary position ,rahul paddles his bicycle to attain a velocity of 6m/s in 30 seconds . calculate the acceleration.

Answer 1

u , initial velocity = 0m/s
v , final velocity = 6m/s
time taken = 30sec

acceleration = (v-u)/t
=> acceleration = (6-0)/30
=> acceleration = 6/30 => 1/5 m/s²
=> acceleration = 0.2 m/s²



hope this helps

Answer 2

$\boxed{\bf \: SOLUTION:-}$

$\rm \underline{ In \: the \: first \: case :-}$

$\rm \: initial \: velocity, \: u =0;$

$\rm \: final \: velocity, \: v=6 \: m \: s^{-1};$

$\rm \: time, \: t=30 \: s.$

$\boxed{\bf \: a \: = \: \frac{v-u}{t}}$

$\rm \: Substituting \: the \: given \: values \: of\: u, \: v \: and\\\rm \: t \: in \: above \: formula, \: we \: get$

$\rm \: a= \frac{(6 \: m \: s^{-1} -0 \: m \: s^{-1}) }{30 \: s}$

$\rm \: \: \: \: \: \: \: \: \: = \: \: 0.2 \: m \: s^{-2}$

$\rm \underline{ In \: the \: second \: case:-}$

$\rm \: initial\: velocity, \: u=6 \: m \: s^{-1} ;$

$\rm \: final \: velocity, \: v=4 \: m \: s^{-1}$

$\rm\: time, \: t= \: 5 \: s.$

$\rm \: Then, \: a= \frac{(4 \: m \: s^{-1} - 6 \: m \: s^{-1}) }{5 \: s}$

$\rm \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \: \: -0.4 \: m \: s^{-2}.$

$\rm \: The \: acceleration \: of \: the \: bicycle \: in \: the\\\rm \: first \: case \: is \: 0.2 \: m \: s^{-2} \: and \: in \: the \: second\\ \rm \: case, it \: is \: -0.4 \: m \: s^{-2}.$

$\boxed{\underline{\tt \: I \: hope \: it's \: helps \: you : )}}$