Starting from the point of origin, a man walks 25 km in a direction 〖30〗^0 below the +x-axis and then walks 30 km along the + y-axis to an endpoint. What is the displacement of the man from the starting point to the ending point?
Answers
Given : Starting from the point of origin, a man walks 25 km in a direction 30° below the +x-axis and then walks 30 km along the + y-axis to an endpoint.
To Find : Displacement of the man from the starting point to the ending point
Solution:
Starts from Origin ( 0 , 0)
man walks 25 km in a direction 30° below the +x-axis
=> angle = - 30°
Distance along x axis = 25cos(-30°) = 25Cos30° = 25√3/2 km
Distance along y axis = 25Sin(-30°) = -25Sin30° =- 25(1/2) = -12.5 km
walks 30 km along the + y-axis to an endpoint.
Hence total displacement along y axis = -12.5 + 30 = 17.5 = 35/2 km
Final coordinates are ( 25√3/2 , 35/2)
Displacement from origin = √{(25√3/2)² + (35/2)²}
= (1/2)√{1875 + 1225}
= (1/2)√3100}
= (1/2) 10√31
= 5√31
Displacement of the man from the starting point to the ending point
5√31 km = 27.84 km
Learn More"
starting from the rest train moves with uniform acceleration of 1.5 ...
brainly.in/question/17655683
An airbus starting from rest attains velocity of 225m/s runs on a ...
brainly.in/question/20228684
Answer:
Starts from Origin ( 0 , 0)
man walks 25 km in a direction 30° below the +x-axis
=> angle = - 30°
Distance along x axis = 25cos(-30°) = 25Cos30° = 25√3/2 km
Distance along y axis = 25Sin(-30°) = -25Sin30° =- 25(1/2) = -12.5 km
walks 30 km along the + y-axis to an endpoint.
Hence total displacement along y axis = -12.5 + 30 = 17.5 = 35/2 km
Final coordinates are ( 25√3/2 , 35/2)
Displacement from origin = √{(25√3/2)² + (35/2)²}
= (1/2)√{1875 + 1225}
= (1/2)√3100}
= (1/2) 10√31
= 5√31
Explanation: