Question

starting from the rest train moves with uniform acceleration of 1.5 metre per second square for 3 minutes calculate the total distance covered by the train​

Answer 1

u=0

3minutes=180seconds

a=1.5m/s²

s=ut+1/2at²

s=0×180+1/2×1.5×180×180

s=24300meters

Answer 2

Given :   starting from the rest train moves with uniform acceleration of 1.5 meter per second square for 3 minutes

To find : the total distance covered by the train​

Step-by-step explanation:

starting from the rest

=>initial velocity u = 0 m/s

moves with uniform acceleration of 1.5 m/s²

=> a = 1.5 m/s²

time = 3 mins = 180 sec

using formula  S = ut + (1/2)at²

=> S = 0 + (1/2)(1.5)(180)²

=> S = 24300 m

24300 m = 24.3 km

=> Distance covered by train   = 24.3 km

Another method

final velocity   v  = u + at   = 0 +  1.5*180    = 270 m/s

Either Distance = (1/2) (u +v) *t  = (1/2)(0 + 270) * 180 = 24300

or V² - U² = 2aS  => 270² = 2(1.5)S  => S = 24300

the total distance covered by the train​ = 24.3 km  

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