Chemistry, asked by hgbh781, 7 months ago

Starting substance for the preparation of CH3Cl is


 (a) CH3OH

 (b) C2H5OH

 (c) CH3CHO

 (d) (CH3)2CO

Answers

Answered by Draxillus
0

Heya,

The answer is (a).

CH3OH can be used for the preparation of CH3Cl by SN2 reaction using the reagent PCl3 or PCl5

Answered by bhargab63
4

Answer:

The correct answer of the question is option (a) CH3OH

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