starts
from
lom
above
the
ground
level
4 An elevator descends into a mine shaft
at the rate of 5M/ min . If the descent
how long will it take to reach - 250
Answers
Answered by
2
Distance descended is denoted by a negative integer,
Initial height =+10 m
Final Depth =−350 m
Total distance to be descended by the elevator =(−350)−(+10)=−360 m
Given, the time is taken by the elevator to descend −6 m=1 minute
Thus, time taken by the elevator to descend −360 m=
(−6)
(−360)
------- [from the formula : speed=
time
distance
]
=60 minutes
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Answered by
0
Answer:
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