Question

Starts from rest and accelerates uniformly with 2 metre per second square at is equals to 10 second a stone is dropped by a person standing on the top of the truck 6 feet height from the ground what is the velocity of the stone at t is equal to 11 second

Answer 1

As we know.

Distance covered =ut+(1/2)at^2

here u = 0 Because, body starts from rest

(1/2)*2*2^2=4

So, distance covered will be 4m