Question

State abd derivw the formula for compression factor at criticak point?

Answer 1

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Using the expression as

Tc = 8a/27RB .....(1) [critical temperature]

pc = a/27b²......(2) [critical pressure]

VC = 3b .......(3) [molar critical volume]

Now putting these values in

Zc =
$\frac{pc \times vc}{r \times tc} = \frac{3}{8}$

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Answer 2

$\underline{\underline{\Huge\mathfrak{Answer ;}}}$

$<b>$
We can use some expression as listed below ;-

$= > tc = \frac{8a}{27rb} .....(1)$

$= > pc = \frac{a}{ {27b}^{2} } .........(2)$

$= > vc = 3b......(3)$
And these values can be putted as ;-

$= > zc = \frac{pc \times vc}{r \times tc} = \frac{3}{8}$

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