Physics, asked by Bobby8497, 11 months ago

State & explain work energy theorum. ​

Answers

Answered by Anonymous
7

 \underline{ \fcolorbox{red}{pink}{ \huge{Answer :)}}}

Work energy theorem states that the work done is equal to the change in kinetic energy

 \sf \fbox{WORK \:  DONE = CHANGE \:  IN \:  KINETIC \:  ENERGY }

It can be written as ,

 \sf \fbox{WORK \:  DONE = \frac{1}{2 } m{(v)}^{2}  -  \frac{1}{2} m {(u)}^{2} }

DERIVATION :

From Newton's 3rd equation of motion ,

➡(v)² - (u)² = 2as

Dividing by m/2 on both sides , we get

➡m(v)²/2 - m(u)²/2 = (2as)m/2

➡Change in kinetic energy = ma(s)

➡Change in kinetic energy = f(s)

Change in kinetic energy = work

  • Force (f) = ma
  • Work (w) = force × displacement

_____________ Keep Smiling ☺

Answered by Anonymous
3

Answer:

hey bobby

Explanation:

here is your answer

the total weight done on an object equals the change in the object kinetic energy and gravitational potential energy

the work energy therom states that the work done on an object by the net force is equal to change it in its kinetic energy

work energy therom states that the change In kinetic energy of an object is equal to the net work done on it by the net force

let us suppose that a body is instally at rest and a force F is applied on a body displace is through along the direction of force

dw = f.ds = fds

according to Newton's second law

f = \: ma

where s is accelerated produced an applying the force

dw \:  = mads \:  = m \frac{dv}{dt} ds

w =  \frac{1}{2}  {mv}^{2}  -  \frac{1}{2}  {mv}^{2}

work done on a body by a force is equal to the change in its kinetic energy

thanku

bobby

Similar questions