Question

state an expression for moments of inertia of ring about its central axis​

Answer 1

Explanation:

The moment of inertia of a circular ring about an axis perpendicular to its plane passing through its centre is equal to MR2, where M is the mass of the ring and R is the radius of the ring. Hence, I=MR2.

Answer 2

Answer:

The moment of inertia of a circular ring about an axis perpendicular to its plane passing through its centre is equal to MR2, where M is the mass of the ring and R is the radius of the ring.