state an expression for moments of inertia of ring about its central axis
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1
Answer:
The moment of inertia of a circular ring about an axis perpendicular to its plane passing through its centre is equal to MR2, where M is the mass of the ring and R is the radius of the ring.
Hence, I=MR2
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32
Answer:
Moment of Inertia of ring about an axis perpendicular to its plane is I=MR^2
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