State an expression for the moment of inertia of a thin, uniform rod about an axis passing
through its centre and perpendicular to its length.
Answers
What would you like to ask?
11th
Physics
Systems of Particles and Rotational Motion
Moment of Inertia
Moment of Inertia of a thin...
PHYSICS
Asked on October 15, 2019 byPrakrati Bukhari
Moment of Inertia of a thin uniform rod rotating about the perpendicular axis passing through its centre is I. If the same rod is bent into a ring and its moment of inertia about its diameter is I′, then the ratio I′I is
A
3π2/2
B
8π2/3
C
2π2/3
D
5π2/3
HARD
Share
Study later
VIDEO EXPLANATION

ANSWER
Let the length of the rod be L and mass be M.
Then, moment of inertia of the rod about a perpendicular axis through the center is given by:
I=12ML2......(i)
Now, the rod is bent in the shape of a ring. Hence, the circumference of the ring equals the length of the rod.
∴L=2πR...............(ii) where R is the radius of the ring
Moment of inertia of ring about its diameter is given by:
I′=2MR2.....................(iii)
From (i), (ii) and (iii),
I′I=2MR212ML
Explanation:
please make me brainlist