Question

state and derive work energy theorem for a constant force​

Answer 1

Answer:

Derivation

For the sake of simplicity, we will consider the case in which the resultant force F is constant in both magnitude and direction and is parallel to the velocity of the particle. The particle is moving with constant acceleration aalong a straight line. The relationship between the net force and the acceleration is given by the equation F = ma (Newton’s second law), and the particle’s displacement d, can be determined from the equation:

v2f=v2i+2advf2=vi2+2ad

obtaining,

d=v2f−v2i2ad=vf2−vi22a

The work of the net force is calculated as the product of its magnitude (F=ma) and the particle’s displacement. Substituting the above equations yields:

W=Fd=mav2f−v2i2a=12mv2f−12mv2i=KEf−KEi=ΔKE

Answer 2

Answer:

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