State and explain ampers circuit law and find the magnetic field at a point in side the solenoid carrying current ?
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~*HEY FRIEND*~
~* THE ANSWER OF YOUR QUESTION IS..*~
✍✍✍✍✍✍✍✍________________________________________j
according to ampere circuit law the line integration of magnetic field along a closed loop is equal to* (mu nod )times of total current inclosed by this closed loop or AMPERE loop .
close integration of B.dl = mu nod I (enclosed)
APPLICATION OF AMPERE CIRCUIT LAW:-
1. TO FIND magnetic field along thin current carrying wire .
2. magnetic field due to thick current carrying wire.
3.magnetic field due to long solenoid.
4.magnetic field due to endless solenoid.
MAGNETIC FIELD DUE TO SOLENOID
¤ INSIDE Bin = mu nod I or mu nod I/L
¤ AT END Bend = mu nod n I/2 or mu nod N I / 2L
HOPE IT WILL HELP YOU
~* THE ANSWER OF YOUR QUESTION IS..*~
✍✍✍✍✍✍✍✍________________________________________j
according to ampere circuit law the line integration of magnetic field along a closed loop is equal to* (mu nod )times of total current inclosed by this closed loop or AMPERE loop .
close integration of B.dl = mu nod I (enclosed)
APPLICATION OF AMPERE CIRCUIT LAW:-
1. TO FIND magnetic field along thin current carrying wire .
2. magnetic field due to thick current carrying wire.
3.magnetic field due to long solenoid.
4.magnetic field due to endless solenoid.
MAGNETIC FIELD DUE TO SOLENOID
¤ INSIDE Bin = mu nod I or mu nod I/L
¤ AT END Bend = mu nod n I/2 or mu nod N I / 2L
HOPE IT WILL HELP YOU
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