Question

★ State and explain Rault's law.


Answer it fast! :-)​

Answer 1

Answer:

Established by French chemist François-Marie Raoult in 1887, it states that the partial pressure of each component of an ideal mixture of liquids is equal to the vapor pressure of the pure component multiplied by its mole fraction in the mixture. ...

Answer 2

❥︎AɴsWᴇʀ:-★

STATEMENT:-

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"It States that , the partial vapour pressure of any volatile component of a solution is equal to the vapour pressure of the pure component multiplied by its mole fraction in the solution".

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Suppose ,

• For a binary solution of two volatile liquids A₁ and A₂ ;
• P₁ and P₂ are their partial vapour pressures and
• x₁ & x₂ are their mole fractions in solution.

Then according to Rault's Law,

➟ p₁ = x₁p₁° & p₂ = x₂p₂°

Where p₁° & p₂° are vapour pressures of pure liquids A₁ & A₂ .

According to Dalton's law of partial pressures the total pressures p is:

P = p₁ + p₂

p = p₁°x₁ + p₂°x₂ .........①

But , as we know x₁ + x₂ = 1

➟ x₁ = 1- x₂.

Substitute x₁ in equation ①

➟ P= p₁°(1 - x₂) + p₂°x₂

➟ P = p₁° - p₁°x₂ + p₂°x₂

➟ P = p₁° + p₂°x₂ - p₁° x₂.

➟ P = p₁° + ( p₂°- p₁° ) x₂

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Composition of vapour phase:-

If we take y₁ and y₂ are the mole fractions of two components in the vapour.

Then,

P₁ = y₁p & P₂ = y₂p

where, p₁ & p₂ are partial pressures of two components in the vapour and P is the total vapour pressures.

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