State and prove cauchy's nth root test
Answers
If C<1 then the series converges absolutely,
if C>1 then the series diverges
if C=1 & limit approaches strictly from above then the series diverges.
otherwise the test is inconclusive (the series may diverge,converge absolutely or converge conditionally)
Proof;
the proof of the convergence of a series∑an is an application of the comparison test.If for all n≥(N some fixed natural number)we have then.Since the geometric series converges so does by the comparison test.Hence ∑an converges absolutely.Note that...implies that...for almost all
If for infinitely many n,then an fails to converge to 0,hence the series is divergent.
Answer:
State and prove Cauchy's nth root test are shown below:
Step-by-step explanation:
Theorem
The root test utilizes the number where "lim sup" represents the limit superior, possibly ∞.
Note that if converges then it equals C and may be used in the root test instead.
The root test states that:
If then the series converges absolutely,
if then the series diverges
if and limit approaches strictly from above then the series diverges.
otherwise, the test is inconclusive (the series may diverge, converge absolutely or converge conditionally).
Proof:
The proof of the convergence of a series ∑ is an application of the comparison test. If for all n≥(N some fixed natural number)we have then. Since the geometric series converges so does the comparison test. Hence ∑ converges absolutely.
If for infinitely many n, then fails to converge to 0, hence the series is divergent.
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