state and prove interior angle theorem for Triangles please answer me correctly
l'm mark the brailist please
Answers
Answer:
The Alternate Interior Angles Theorem states that, when two parallel lines are cut by a transversal , the resulting alternate interior angles are congruent .
So, in the figure below, if k∥l , then ∠2≅∠8 and ∠3≅∠5 .
Two parallel lines cut by a transversal n, with angles labeled 1 through 8
Proof.
Since k∥l , by the Corresponding Angles Postulate ,
∠1≅∠5 .
Therefore, by the definition of congruent angles ,
m∠1=m∠5 .
Since ∠1 and ∠2 form a linear pair , they are supplementary , so
m∠1+m∠2=180° .
Also, ∠5 and ∠8 are supplementary, so
m∠5+m∠8=180° .
Substituting m∠1 for m∠5 , we get
m∠1+m∠8=180° .
Subtracting m∠1 from both sides, we have
m∠8=180°−m∠1 =m∠2 .
Therefore, ∠2≅∠8 .
You can prove that ∠3≅∠5 using the same method.
Step-by-step explanation: