state and prove principal of conservation of momentum
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According to law of conservation of momentum,the momentum of body remains constant before and after a action when no external force acts on the body.
This can be proven by newton's third law
If F is action and R is reaction.[both F and R are forces]
F = -R
F + R = 0 [Which means that no external force is acting]
d(F)/dt + d(R)/dt = 0 [∵ d(F)/dt = P where P is momentum]
d(F+R)/dt = 0
d(P)/dt = 0
As the differentiation of Constant is 0 P is considered as constant now
Hence Proved
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@rishitezreddydhava
This can be proven by newton's third law
If F is action and R is reaction.[both F and R are forces]
F = -R
F + R = 0 [Which means that no external force is acting]
d(F)/dt + d(R)/dt = 0 [∵ d(F)/dt = P where P is momentum]
d(F+R)/dt = 0
d(P)/dt = 0
As the differentiation of Constant is 0 P is considered as constant now
Hence Proved
Please mark this answer as brainlist answer. I have to go to next rank.You will also get some points if u mark a answer as branlist answer.
@rishitezreddydhava
Answered by
6
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Conservation 0f Momentum➫ A system in which the momentum of a system is constant if there are no external forces acting on the system.
Prove: Conservation 0f Momentum:-▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃⤵
➧Let the Body A = m1 & B = m2
➧Let their velocity be u1 & u2
(u1 > u2)
➧Momentum of Body
A = m1u1 & B = m2u2
❱ Initial & Final momentum of System
➾ m1u1 + m2u2
◉ Body A exert force of Action
➾ Fᴀʙ on Body B.
◉ Body B exert force of Reaction
➾ Fʙᴀ on Body A.
▸ Fᴀʙ = Body A
➾ m1 (v1 - u1) / t
▸ Fʙᴀ = Body B
➾ m2 (v2 - u2) / t
▸ Since, Action = - reaction
▸ So, Fᴀʙ = - Fʙᴀ
m1 (v1 - u1) / t = - m2 (v2 - u2) / t
▸ m1v1 - m1u1 = m2v2 + m2u2
▸ m1v1 - m2v2 = m1u1 + m2u2...✔
_________
Thanks...✊
✭✮ӇЄƦЄ ƖƧ ƳƠƲƦ ƛƝƧƜЄƦ✮✭
┗─━─━─━─━∞◆∞━─━─━─━─┛
Conservation 0f Momentum➫ A system in which the momentum of a system is constant if there are no external forces acting on the system.
Prove: Conservation 0f Momentum:-▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃⤵
➧Let the Body A = m1 & B = m2
➧Let their velocity be u1 & u2
(u1 > u2)
➧Momentum of Body
A = m1u1 & B = m2u2
❱ Initial & Final momentum of System
➾ m1u1 + m2u2
◉ Body A exert force of Action
➾ Fᴀʙ on Body B.
◉ Body B exert force of Reaction
➾ Fʙᴀ on Body A.
▸ Fᴀʙ = Body A
➾ m1 (v1 - u1) / t
▸ Fʙᴀ = Body B
➾ m2 (v2 - u2) / t
▸ Since, Action = - reaction
▸ So, Fᴀʙ = - Fʙᴀ
m1 (v1 - u1) / t = - m2 (v2 - u2) / t
▸ m1v1 - m1u1 = m2v2 + m2u2
▸ m1v1 - m2v2 = m1u1 + m2u2...✔
_________
Thanks...✊
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