Math, asked by pt227485, 7 months ago

state and prove pythogoros theroms​

Answers

Answered by saherjiwani
0

Step-by-step explanation:

Pythagoras theorem states that “ In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides”. The sides of the right-angled triangle are called base, perpendicular and hypotenuse . Proof: ... ∠BAD = ∠BAC i.e. ∠A is common in both triangles.

Answered by namosprime
2

Answer:

Statement: In a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

Given: ABC is a triangle in which ∠ABC=90

Construction: Draw BD⊥AC.

Proof:

In △ADB and △ABC

∠A=∠A [Common angle]

∠ADB=∠ABC [Each 90

]

△ADB∼△ABC [A−A Criteria]

So,

AB

AD

=

AC

AB

Now, AB

2

=AD×AC (1)

Similarly,

BC

2

=CD×AC (2)

Adding equations (1) and (2) we get,

AB

2

+BC

2

=AD×AC+CD×AC

=AC(AD+CD)

=AC×AC

∴AB

2

+BC

2

=AC

2

[henceproved]

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