Question

state and prove 'remainder theorai'


plz do it fast​

Answer 1

Answer:

Statement of Remainder Theorem:

Let f(x) be any polynomial of degree greater than or equal to one and let ' a' be any number. If f(x) is divided by the linear polynomial (x-a) then the remainder is f(a).

Answer 2

Step-by-step explanation:

statement:

Let f(x) be any polynomial of degree greater than or equal to one and let ‘ a‘ be any number.

If f(x) is divided by the linear polynomial (x-a) then the remainder is f(a).

Remainder Theorem Proof:

Let f(x) be any polynomial with degree greater than or equal to 1.

Further suppose that when f(x) is divided by a linear polynomial p(x) = ( x -a), the quotient is q(x) and the remainder is r(x).

In other words , f(x) and p(x) are two polynomials such that the degree of f(x) >= degree of p(x) and p(x) not equal to 0

then we can find polynomials q(x) and r(x) such that, where r(x) = 0 or degree of r(x) < degree of g(x).

By division algorithmf(x) = p(x) . q(x) + r(x)

∴ f(x) = (x-a) . q(x) + r(x) [ here p(x) = x – a ]

Since degree of p(x) = (x-a) is 1 and degree of r(x) < degree of (x-a)

∴ Degree of r(x) = 0

This implies that r(x) is a constant , say ‘ k ‘

So, for every real value of x, r(x) = k.

Therefore f(x) = ( x-a) . q(x) + kIf

x = a,

then f(a) = (a-a) . q(a) + k = 0 + k = k

Hence the remainder when f(x) is divided by the linear polynomial (x-a) is f(a).

I hope it will help you