state and prove remainder therom.
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Hey buddy here is ur answer !!!!!!!
Polynomial remainder theorem.
It states that the remainder of the division of a polynomial by a linear polynomial is equal to. In particular, is a divisor of if and only if a property known as the factor theorem.
a = bq + r
hope u like my answer ...
Polynomial remainder theorem.
It states that the remainder of the division of a polynomial by a linear polynomial is equal to. In particular, is a divisor of if and only if a property known as the factor theorem.
a = bq + r
hope u like my answer ...
Answered by
4
Remainder theorem is an application of polynomial long division. When we divide a polynomial F(x) by x - a, the remainder will be F(a) and if F(a) = 0, then (x - a) is a factor of the expression F(x). Conversely, for the expression F(x), if F(a) = 0, then (x - a) is a factor of F(x) and "a" is its root.
proof: let f(x) is divided by (x-a), the quotient is g(x) and the remainder is r(x).
then degree r(x)<degree(x-a)
degree r(x)<1
degree r(x)=0
r(x) is constant, equal to r say
Thus when f(x) is divided by (x-a) then the quotient is g(x) qnd remainder is r.
f(x)=(x-a) *g(x)+r....... 1
putting x=a in 1 we get r=f(a)
Thus when
proof: let f(x) is divided by (x-a), the quotient is g(x) and the remainder is r(x).
then degree r(x)<degree(x-a)
degree r(x)<1
degree r(x)=0
r(x) is constant, equal to r say
Thus when f(x) is divided by (x-a) then the quotient is g(x) qnd remainder is r.
f(x)=(x-a) *g(x)+r....... 1
putting x=a in 1 we get r=f(a)
Thus when
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