State and prove RHS Congruency Rule.
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RHS congruency rule:- if the right angle, a hypotenuse and one side(base/perpendicular) of two triangles are equal then they are congruent.
Usually, this is called SSA rule and is not applicable in normal circumstances.
Proof:
Q. AB is a line segment. P & Q are pts on opp. sides of AB such that each is equidistant from A & B. Show that PQ is perpendicular bisector of AB
A. AP=BP (GIVEN)
AQ=BQ("")
PQ=PQ(COMMON)
∆PAQ=∆BPQ(SSS)
<APQ=<BPQ(CPCT)
AP=BP(GIVEN)
< APC=<BPC(<APQ = <BPQ PROVED)
PC=PC(COMMON)
∆PAC =∆PBC
AC=BC(CPCT)
<ACP+<BCP=180° (LINEAR PAIR)
2<ACP=180°
<ACP=90°
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Usually, this is called SSA rule and is not applicable in normal circumstances.
Proof:
Q. AB is a line segment. P & Q are pts on opp. sides of AB such that each is equidistant from A & B. Show that PQ is perpendicular bisector of AB
A. AP=BP (GIVEN)
AQ=BQ("")
PQ=PQ(COMMON)
∆PAQ=∆BPQ(SSS)
<APQ=<BPQ(CPCT)
AP=BP(GIVEN)
< APC=<BPC(<APQ = <BPQ PROVED)
PC=PC(COMMON)
∆PAC =∆PBC
AC=BC(CPCT)
<ACP+<BCP=180° (LINEAR PAIR)
2<ACP=180°
<ACP=90°
✓✓✓✓✓✓✓✓✓✓✓✓✓✓✓✓✓
Please mark as brainliest
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