Question

State and prove RHS Congruency Rule.

Answer 1

RHS congruency rule:- if the right angle, a hypotenuse and one side(base/perpendicular) of two triangles are equal then they are congruent.

Usually, this is called SSA rule and is not applicable in normal circumstances.

Proof:
Q. AB is a line segment. P & Q are pts on opp. sides of AB such that each is equidistant from A & B. Show that PQ is perpendicular bisector of AB


A. AP=BP (GIVEN)

AQ=BQ("")

PQ=PQ(COMMON)

∆PAQ=∆BPQ(SSS)


<APQ=<BPQ(CPCT)




AP=BP(GIVEN)

< APC=<BPC(<APQ = <BPQ PROVED)

PC=PC(COMMON)


∆PAC =∆PBC



AC=BC(CPCT)

<ACP+<BCP=180° (LINEAR PAIR)

2<ACP=180°

<ACP=90°

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