Question

state and prove the Pythagoras theorem​

Answer 1

Step-by-step explanation:

Pythagoras theorem states that “ In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides”. The sides of the right-angled triangle are called base, perpendicular and hypotenuse . Proof: ... ∠BAD = ∠BAC i.e. ∠A is common in both triangles.

Answer 2

we get

AB² + BC² = AD × AC + CD × AC

=AC(AD + CD)

=AC×AC

therefor

AB²+BC²=AC²